218k views
3 votes
A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle. As the camera zooms out, the length l and width w of the . rectangle increase at a rate of 3 km/sec. How long does it take for the area A to be at least 4 times its original size?

A.) 4.94 sec
B.) 3.28 sec
C.) 9.7 sec
D.) 1.33 sec

1 Answer

3 votes
Given:

L1 = original length = 4 km
W1 = original width = 4 km
A1 = original area = 4*4 = 16 km^2
A2 = 4(16) = 64 km^2

Given the second area, we can conclude that the lengths and widths of the zoomed out photograph should both be 8 km.

Given that the zooming occurs at 3 km/sec, the amount of time needed for the lengths and widths to zoom out from 4 km to 8 km is shown below:

8km - 4km / 3km/s = 4 / 3 = 1.33 seconds

Therefore, the correct answer is D.

User Tim Hoffman
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories