Question

Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium-133 atom complete during one mosquito wing beat?

Answer 1

The radiation from a cesium-133 atom completes approximately 0.968 cycles of oscillation during one mosquito wing beat.

Step-by-step explanation:

The frequency of the mosquito wing beats is given as 620 beats per second.

To calculate the number of cycles of oscillation completed by the radiation from a cesium-133 atom during one wing beat, we need to find the time period of each oscillation.

The time period is the inverse of the frequency, so the time period T is given by T = 1/frequency. Plugging in the values, we get T = 1/620.

The number of cycles completed during one wing beat can be found by dividing the time period of each oscillation by the time period of one wing beat.

The number of cycles N is given by N = T/T_wing_beat, where T_wing_beat is the time period of one wing beat. Plugging in the values, we get N = (1/620)/(1/600), which simplifies to N = 600/620.

Therefore, the radiation from a cesium-133 atom completes approximately 0.968 cycles of oscillation during one mosquito wing beat.

Answer 2

Given: buzzing frequency = 620 wing beats / second
cesium-133 atom = 9,192,631,770 cycles/ second

Dividing the number of cesium-133 atom cycles by the amount of wing beats, the following is obtained:

(9,192,631,770 cycles / second) / (620 wing beats / second)
14,826,825.44 cycles / wing beat