Answer:
The length and the width of another rectangle are 115 meters and 100 meters
Explanation:
Let us solve the question
∵ A rectangular field is 90 meters wide and 125 meters long
∴ The length = 125 m
∴ The width = 90 m
∵ The perimeter of the rectangle = 2(length + width)
→ Substitute the value of the length and the width in the rule
∴ The perimeter of the rectangle = 2(125 + 90)
∴ The perimeter of the rectangle = 430 m
∵ The area of the rectangle = length × width
→ Substitute the value of the length and the width in the rule
∴ The area of the rectangle = 125 x 90
∴The area of the rectangle = 11250 m²
We need to find another rectangle with the same perimeter but larger in area, to do that make the length and width closed in values
∵ The length = 125 m and the width = 90 m
→ Subtract 10 from the length and add it to the width
∴ The new length = 125 - 10 = 115 m
∴ The new width = 90 + 10 = 100 m
→ Find the perimeter and the area of the new rectangle
∵ The perimeter of the new rectangle = 2(115 + 100)
∴ The perimeter of the new rectangle = 430 m ⇒ the same perimeter
∵ The area of the new rectangle = 115 × 100
∴ The area of the new rectangle = 11500 m² ⇒ larger than the original area
∴ The length and the width of another rectangle are 115 m and 100 m