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Find the horizontal asymptote of f(x)=x^2+3x+6/x^2+1

Find the horizontal asymptote of f(x)=x^2+3x+6/x^2+1
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Find the horizontal asymptote of f(x)=x^2+3x+6/x^2+1

User Mrhallak
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1 Answer

4 votes

Answer:

  • y = 1

Explanation:

Horizontal asymptote of the given function is y = 1

Both numerator and denominator have same degree of two

Refer to attached graph

Find the horizontal asymptote of f(x)=x^2+3x+6/x^2+1-example-1
User Adam Hupp
by
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