Question

What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? a. 11. b. 25. c. 30. d.25. e.36

Answer 1

The value of n such that the expression x² + 11x + n is a perfect square trinomial can be determined by taking the formula: 11 = 2b where b is a real number. b is equal to 11/2. The third term is equal to (11/2)^2 equal to 121/4 equal to 30.25.

Answer 2

The value of n is 30.25.

Explanation:

The given expression is

`x^2+11x+n` ....(1)

The perfect square trinomial are defined as

`(x+y)^2=x^2+2xy+y^2` .....(2)

On comparing (1) and (2), we get

`2y=11`

`y=(11)/(2)`

The given expression is perfect square trinomial if

`n=y^2`

`n=((11)/(2))^2`

`n=(121)/(4)`

`n=30.25`

Therefore the value of n is 30.25.