Question

The value of x varies directly with y, and whenX= 2/3, y = 6. Find the value of y when x = 10-24A.y=9B.y=4C. y=93D.y=1

Answer 1

Problem

Solution

for this case we know that when x =2/3 , y= 6

`10(1)/(3)=(10\cdot3+1)/(3)=(30+1)/(3)=(31)/(3)`

Then we want to find the value of y= ? when x= 10 1/3 = 31/3 and we can do this:

6/(2/3) = y/(31/3)

`(6)/((2)/(3))=(y)/((31)/(3))`
`y=(31)/(3)\cdot(6)/((2)/(3))=(31)/(3)\cdot(3)/(2)\cdot(6)/(1)=(31\cdot3\cdot6)/(3\cdot2\cdot1)=93`

And solving for y we got:

y = (3/2) * 6 * (31/3) = 31*3 = 93

C. y= 93