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Question 5) The diameter of a sphere with a surface area of 81 pi square yards. Part b Find the volume of the composite solid. Somehow, I’m getting the wrong answer that’s not matching the key.

Question 5) The diameter of a sphere with a surface area of 81 pi square yards. Part-example-1
User Iksemyonov
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1 Answer

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Given:


\begin{gathered} R=4in \\ h=7in \\ H=15in \end{gathered}

find: volume of the given figure.

Step-by-step explanation: volume of the composite solid=volume of cone + volume of cylinder .

we know volume of cone is


\begin{gathered} =(\pi r^2h)/(3) \\ =((3.14)(16)(7))/(3) \\ =117.23in^3 \end{gathered}

and the volume of the cylinder is


\begin{gathered} =\pi r^2H \\ =(3.14)(16)(15) \\ =753.6in^3 \end{gathered}

Hence the volume of the composite solid is


\begin{gathered} 753.6+117.23 \\ =870.83in^3 \end{gathered}

(a) given: the surface area of the sphere is 81pi square yards.

find: the diameter of the sphere.

Explanation: we know that the surface area of the sphere is


\begin{gathered} 4\pi r^2=81\pi \\ r^2=(81)/(4) \\ r=(9)/(2) \\ r=4.5yards \end{gathered}

Hence the diameter is equal to twice of the radius


4.5*2=9yards

User Akidi
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