Question

A rectangle has a length of 9025 in and a width of 36 in.a. Find the Perimeter b. Find the Area

Answer 1

Given:

`\text{length(l)}=9025\text{ in ; width(w)=36 in}`
`\begin{gathered} \text{Perimeter of a rectangle=2(l+w)} \\ \text{Perimeter of a rectangle=}2(9025+36) \\ \text{Perimeter of a rectangle=}2(9061) \\ \text{Perimeter of a rectangle=}18122\text{ in.} \end{gathered}`
`\begin{gathered} \text{Area of a rectangle=l}* w \\ \text{Area of a rectangle=}9025*36 \\ \text{Area of a rectangle=}324900in^2 \end{gathered}`