menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
Solve the system by substitution. 6x + 3y = -6 2x + y = -2
asked
Mar 5, 2017
56.5k
views
5
votes
Solve the system by substitution.
6x + 3y = -6
2x + y = -2
Mathematics
high-school
Alasarr
asked
by
Alasarr
8.1k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
2
Answers
4
votes
Solutions
First Lets solve for this equation
Therefore this given equation is a
dependent system.
Solve for
There are too many solutions to these equations.
Gerty
answered
Mar 8, 2017
by
Gerty
8.2k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
3
votes
6x + 3y = -6
2x + y = -2
Solve both equations for the same variable, in this case, I'll solve for y.
2x + y = -2 Subtract 2x from both sides
y = -2x -2
6x + 3y = -6 Subtract 6x from both sides
3y = -6x -6 Divide both sides by 3
y = -2x -2
Once you have them solved you can set them equal to each other and solve.
-2x -2 = -2x -2
But, these two equations are the same, so any number you put in for x will work. The answer to the system is
infinite solutions
.
Thlim
answered
Mar 12, 2017
by
Thlim
7.6k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.5m
questions
12.2m
answers
Other Questions
How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement how thick must the cement be to cover field
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org