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express 1400 as a product of its prime factors in index form write the prime factors in ascending order?

User Denispyr
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1 Answer

8 votes

Answer:


1400=2^3*5^2*7

Explanation:

Prime Factors

The first prime numbers are:

{1,3,5,7,11,13,...}

To find the prime factors of any integer number, we successively divide the number by all the possible prime numbers, probably more than once.

Let's find the prime factors of 1400.

Dividing by 2 while possible:

1400/2 = 700

700/2 = 350

350/2 = 175

3 is not a divisor of 175, so we try 5:

175/5 = 35

35/5 = 7

Since the last result is a prime number, no more tries are necessary. The product of prime factors in index form is:


\boxed{1400=2^3*5^2*7}

User Lucamug
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