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(143(5) + 67)5 __________ A. 1950 B. 1955 C. 1956 D. 1953

(143(5) + 67)5 __________ A. 1950 B. 1955 C. 1956 D. 1953
146k views
4 votes
(143(5) + 67)5 __________

A.

1950
B.

1955
C.

1956
D.

1953

User Hetzroni
by
7.5k points

1 Answer

6 votes
Solutions

To solve the given question we have to use BRDMAS. BEDMAS is the acronym for

Brackets then Exponents then Division/Multiplication and then Addition/Subtraction.


(715+67)*5


715+67 = 782


= 782*5


3910
User Alex DiCarlo
by
7.8k points
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