How would you classify a solution if [OH-] = 4.2 x 10-8 M?

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asked May 25, 2017 156k views

2 Answers

Jason Day · Answer 1 · 2017-05-29T15:32:29+0000

Answer: Slightly acid, almost neutral.

pOH = -log [OH -] = - log [4.2 x 10^-8] = 7.38

pH + pOH = 14 ==> pH = 14 - pOH = 14 - 7.38 = 6.62.

Remember: 7 is neutral, below 7 is acid. This solution is almost neutral.

How would you classify a solution if [OH-] = 4.2 x 10-8 M?

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