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How would you classify a solution if [OH-] = 4.2 x 10-8 M?
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How would you classify a solution if [OH-] = 4.2 x 10-8 M?

User Enes Islam
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2 Answers

4 votes

wrong answer I just took the test

User Yu Fu
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Answer: Slightly acid, almost neutral.

pOH = -log [OH -] = - log [4.2 x 10^-8] = 7.38

pH + pOH = 14 ==> pH = 14 - pOH = 14 - 7.38 = 6.62.

Remember: 7 is neutral, below 7 is acid. This solution is almost neutral.
User Jason Day
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