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Divide √9x2 by √18y2

2 Answers

3 votes

√(9x^2)=3|x|\\\\√(18y^2)=√(9\cdot2)|y|=3|y|\sqrt2\\\\therefore:\\\\√(9x^2):√(18y^2)=(3|x|)/(3|y|\sqrt2)=(|x|)/(|y|\sqrt2)\cdot(\sqrt2)/(\sqrt2)=(|x|\sqrt2)/(2|y|)
User Rasmus Faber
by
8.1k points
1 vote

Answer:√2x/2y

Explanation:

By indices,

√9x²/√18y²

= (√9 × √x²)/ (√18 × √y²)

= (3 × x)/{(√2×9) × y}

= 3x/3√2y

= x/√2y

Rationalizing this,

x/√2y × √2/√2

= √2x/2y.

User TheMrbikus
by
8.9k points

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