179,603 views
23 votes
23 votes
Minerva is trying to estimate 55. She uses this table of values:Square 7.02 7.12 7.22 7.32 7.42 7.52Value49.0 50.4 51.8 53.3 54.8 56.3Square 7.62 7.72 7.82 7.92 8.02Value 51.8 59.3 60.8 62.4 64.0What should she do next to find 55 to the nearest hundredth?A. She should estimate that 55 is 7.50.B. She should find the average of 7.4 and 7.5.C. She should find the squares of numbers between 7.5 and 7.6.D. She should find the squares of numbers between 7.4 and 7.5.

User Alexey Egorov
by
2.6k points

1 Answer

21 votes
21 votes

To estimate the number 55, the option A is not correct because 7.50 squared equals 56.25. That is already higher than the number 55. Option B is correct because the average of 7.4 and 7.5 equals 7.45. The square of 7.45 equals 55.5025 which is approximately 55.

Option C is not correct because the squares of numbers between 7.5 and 7.6 is already greater than the number 55.

Option D is also not correct because the squares of the numbers between 7.4 and 7.5 exceeds the number 55.

The correct option is B

User Valterriann
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.