Question

how many liters of a 20% alcohol solution should be mixed with a 50 liters of a 60% alcohol solution to obtain a 30% solution?

Answer 1

Hope you understand this :)

Answer 2

(0.20*x+50*0.60)(x+50) = 0.30 <=>0.20*x + 30 = 0.30*x + 15 <=> 30 - 15 = 0.30*x - 0.20*x <=> 15 = 0.10*x <=> x = 15*(100/10) <=> x = 150;