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The length of a rectangle is 12 inches and the perimeteris is 56 inches Find the with of rectangle

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x - the width of a rectangle
12 in - the length of a rectangle
56 in - the perimeter of a rectangle

2x + 2 · 12 = 56
2x + 24 = 56 |subtract 24 from both sides
2x = 32 |divide both sides by 2
x = 32 (in)

Answer: The width of a rectangle is 32 in.
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