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Solve the triangle.

a = 10, b = 23, C = 95°

User Joyann
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1 Answer

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c² = a² + b² - (2ab * cosC)
c² = 10² + 23² - (2 * 10 * 23 * cos95)
c² = 100 + 529 - (460 * -.08715)
c² = 629 - (-40.1)
c² = 669.1
c = 25.87

(Sin C) / C = (Sin A) / A
(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85
(10 * Sin95) / 25.87 = Sin A
A = arcsin ((10 * sin95) / 25.87)
A = 22.65º

B = 180 - A - C
B = 180 - 95 - 22.65
B = 62.35º

I hope this helps. Have a good day.
User Jcmitch
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