Question

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 105°, a = 12 cm, c = 19 cm

Answer 1

The area of triangle is
`110.10cm^(2)`

Explanation:

It is given that AB=19cm, BC=12cm and ∠B=105°

Now, Area of the triangle ABC=
`(1)/(2)acsinB`

=
`(1)/(2){*}12{*}19{*}sin105^(\circ)`

=
`6{*}19{*}(0.965)`

=
`110.10cm^(2)`

Thus, the area of triangle is
`110.10cm^(2)`