Question

If a gas has a volume of 284 liters and a pressure of 159 atm and the volume changes to 653 liters what is the new pressure ?

Answer 1

The new pressure = 69.2 atm

Step-by-step explanation

Given:

Initial volume, V₁ = 284 L

Initial pressure, P₁ = 159 atm

Final volume, V₂ = 653 L

What to find:

The new pressure, P₂ when the volume changes to 653 L.

Step-by-step solution

The new pressure, P₂ when the volume changes to 653 L can be calculated using Boyle's law equation.

`\begin{gathered} P_1V_1=P_2V_2 \\ \\ \Rightarrow P_2=(P_1V_1)/(V_2) \end{gathered}`

Putting the values of the given parameters into the equation, we have

`P_2=\frac{159\text{ }atm*284\text{ }L}{653\text{ }L}=(45156)/(653)=69.2\text{ }atm`

The new pressure = 69.2 atm