Answer:
Option A. is the correct option.
Explanation:
It is given In the triangle ABC and triangle ADC
Sides AB is congruent to side AD and side AC is common in both the triangles
∠ACD ≅ ∠ACB = 90°
Since triangle ABD is an isosceles triangle, so perpendicular drawn from A to side BD will equally bisect the side BD and ∠ABC ≅ ∠ADC
BC ≅ CD
Therefore, by ASA property in ΔABC and ΔADC
∠ABC ≅ ∠ADC
∠ACB ≅ ∠ACD ≅ 90°
And BC ≅ CD
Therefore, ΔABC ≅ ΔADC
Option A. will the answer.