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A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles of butane. What is the total pressure of the mixture inside the flask?
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Sep 25, 2017
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A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles of butane. What is the total pressure of the mixture inside the flask?
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Sylvain GIROD
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Applying the general gas equation : PV=nRT
V = 1.50 litres
R =
0.08205746 L atm/K mol
T =
25°C = 25+273 = 298 K
n =
0.158 moles+0.09 moles+
0.044 moles = 0.292 moles
Re arranging the equation:
P = nRT / V = (0.158 + 0.09 + 0.044) mol x (0.08205746 L atm/K mol)
x (25 + 273)K / (1.50 L)
= 4.76 atm
= 482 kPa
= 3617 mmHg
Eltiare
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Oct 1, 2017
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Eltiare
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