Question

Solving Equatic Equations:4x²+x-3=0

Answer 1

S={-1,3/4}

1) Let's solve this quadratic equation

4x²+x -3=0

Let's solve that using the traditional way. Applying the Resolutive Formula for Quadratic Equations. First, we find the discriminant Delta:

`\begin{gathered} \Delta=\text{ 1²-4(4)(-3) }=1\text{ +}48=\text{ 49} \\ x\text{ =}\frac{-b+-\sqrt[]{49}}{2a} \\ x_1=(-1+7)/(8)=(3)/(4) \\ x_2=(-1-7)/(8)=-1 \end{gathered}`

2) So the Solution set is S={-1, 3/4} the roots for that quadratic equation, where y=0 at x=-1, and x=3/4