169k views
3 votes
Which point lies on a circle with a radius of 5 units and center at P(6, 1)?

A) Q(1, 11)
B) R(2, 4)
C) S(4, -4)
D) T(9, -2)

User Jurrian
by
7.6k points

2 Answers

6 votes
The general equation for a circle centered at (h,k) with radius, R, is
(x-h)^2 + (y-k)^2 = R^2

Putting the values in formula,
(x-6)^2 + (y-1)^2 = 5^2
Putting the coordinates (2, 4) of the answer B(2-6)^2 + (4-1)^2 = 25
(-4)^2 + 3^2 = 25
16 + 9 = 25
25 = 25
R.H.S = L.H.S
So according to above solution,

B) R(2, 4), is the correct answer.

User Wups
by
9.0k points
7 votes
An equation of a circle:

(x - a)² + (y - b)² = r²

(a; b) - a coordinates of a center
r - a radius

r = 5; P(6; 1) ⇒ a = 6 and b = 1

therefore

(x - 6)² + (y - 1)² = 5²

check:
A) Q(1; 11)
L = (1 - 6)² + (11 - 1)² = (-5)² + 10² = 25 + 100 = 125
R = 25
L ≠ R

B) R(2; 4)
L = (2 - 6)² + (4 - 1)² = (-4)² + 3² = 16 + 9 = 25
R = 25
L = R - CORRECT

C) S(4; -4)
L = (4 - 6)² + (-4 - 1)² = (-2)² + (-5)² = 4 + 25 = 29
R = 25
L ≠ R

D) T(9; -2)
L = (9 - 6)² + (-2 - 1)² = 3² + (-3)² = 9 + 9 = 18
R = 25
L ≠ R

Answer: B) R(2; 4).
User Luca Trazzi
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories