Question

find the equation of a line , in slope-intercept form of a line that passes through the point (-5,-1) and is parallel to the line -2x+4y=8

Answer 1

For this case we need to have the same slope and we can find it from the original equation and we got:

4y = 8+2x

y = 2 +1/2x

So then the slope is :

`m=(1)/(2)`

We need to have the same slope and we can do the following:

`-1=(1)/(2)(-5)+b`

And solving for b we got:

`b=-1+(5)/(2)=(3)/(2)`

And then the equation would be given by:

`y=(1)/(2)x+(3)/(2)`