Find the exact value of the real number y. y = csc^-1(1)

Question

asked Jun 8, 2017 111k views

1 Answer

Lfmunoz · Answer 1 · 2017-06-14T03:09:47+0000

Answer:

The exact value of the real number y is
$y=(\pi)/(2)$

Explanation:

Given : Expression
$y=\csc^(-1)(1)$

To find : The exact value of the real number y?

Solution :

We can write the expression as

$y=\csc^(-1)(1)$

$\csc y=1$

$(1)/(\sin y)=1$

$\sin y=1$

$\sin y=\sin ((\pi)/(2))$

$y=(\pi)/(2)$

Therefore, The exact value of the real number y is
$y=(\pi)/(2)$