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Find the exact value of the real number y.

y = csc^-1(1)

User Osie
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1 Answer

1 vote

Answer:

The exact value of the real number y is
y=(\pi)/(2)

Explanation:

Given : Expression
y=\csc^(-1)(1)

To find : The exact value of the real number y?

Solution :

We can write the expression as


y=\csc^(-1)(1)


\csc y=1


(1)/(\sin y)=1


\sin y=1


\sin y=\sin ((\pi)/(2))


y=(\pi)/(2)

Therefore, The exact value of the real number y is
y=(\pi)/(2)

User Lfmunoz
by
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