Question

The calculated yield for iron sulfide was 16.8 grams but the measured yield was 11.6 g what is the percent yield?

2FeBr3+3Na2S=Fe2S3 + 6NaBr

Answer 1

Answer: The percentage yield of iron sulfide for the reaction is 69.04 %.

Step-by-step explanation:

For the given chemical equation:

`2FeBr_3+3Na_2S\rightarrow Fe_2S_3+6NaBr`

To calculate the percentage yield of a compound, we use the following equation:

`\%\text{ yield}=\frac{\text{Measured yield}}{\text{Calculated yield}}* 100`

We are given:

Measured yield of iron sulfide = 11.6 g

Calculated yield of iron sulfide = 16.8 g

Putting values in above equation, we get:

`\%\text{ yield of iron sulfide}=(11.6g)/(16.8g)* 100=69.04\%`

Hence, the percentage yield of iron sulfide for the reaction is 69.04 %.

Answer 2

Percent yield = [actual yield] / [theoretical yield] * 100

Percent yield = 11.6/16.8 * 100 = 69.05%