Question

Sammy Sosa swings at a 0.15 kg baseball and accelerates it at a rate of3.0 x 10^4 m/s2. How much force does Sosa exert on the ball?

Answer 1

Using Newton's second law, the force that Sammy Sosa exerts on the baseball is calculated to be 4500 Newtons, with a mass of the ball at 0.15 kg and acceleration at 3.0 x 10^4 m/s^2.

Step-by-step explanation:

The force that Sammy Sosa exerts on the baseball can be calculated using Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by the acceleration of the object. The formula for this is F = ma, where F is the force, m is the mass of the baseball, and a is the acceleration of the baseball.

Given that the mass (m) of the baseball is 0.15 kg and the acceleration (a) is 3.0 x 104 m/s2, we can calculate the force as follows:

F = 0.15 kg × 3.0 x 104 m/s2
F = 4500 N

Hence, the force exerted by Sammy Sosa on the baseball is 4500 Newtons.

Answer 2

Given:

The mass of the ball is m = 0.15 kg

The acceleration of the ball is

`a=3*10^4\text{ m/s}^2`

To find the force.

Step-by-step explanation:

The force can be calculated by the formula

`F=\text{ ma}`

On substituting the values, the force will be

`\begin{gathered} F=0.15*3*10^4 \\ =4500\text{ N} \end{gathered}`

Thus, the Sosa exerts 4500 N of force on the ball.