Question

Help me find the value of the new standard deviation. Thanks!

Answer 1

Hello,


`$\sum_(i=1)^8 x_(i) =13*8=104\\$`


`$\sum_(i=1)^7 x_(i) =11*7=77\\$`

`x_(8) =104-77=27`

Var=7.71²=59.4441

`m_(2) - m_(1) ^2=59.4441\\ m_(2) 59.4441+13^2=228.441\\\\ \sum_(i=1)^8x_i=228.4441*8=1827.5528\\\\ \sum_(i=1)^7x_i=1827.5528-27^2=1098.5528\\\\ m'_(2) - m'_(1) ^2= (1098.5528)/(7)-11^2=35.93611...\\\\ \sigma'= √(35.93611...) =5.994673...`