Question

Hydrogen sulfide gas is bubbled through excess

potassium hydroxide solution.
H2S + 2OH– → S2– + 2H2O

Write the balanced chemical equation excluding spectator ions. How do you get there from
H2S + KOH -> K2S + H2O ?

Answer 1

The balanced chemical equation excluding spectator ions is 2H2S + 2KOH -> K2S + 2H2O.

Step-by-step explanation:

To balance the chemical equation H2S + KOH -> K2S + H2O, we need to write the balanced equation excluding spectator ions. Spectator ions are ions that do not participate in the reaction and remain unchanged throughout the reaction. In this case, the spectator ions are K+ and OH-. The balanced chemical equation without spectator ions is:

2H2S + 2KOH -> K2S + 2H2O

Answer 2

separate the atoms from the molecules and give them charges
H2S = 2 H+ + S^-2
double replacement reaction. AB + CD = AD + CB
Hydrogen sulfide gas is bubbled through excess potassium hydroxide solution, but you only put H2S + 2OH– → S2– + 2H2O
H2S + KOH -> K2S + H2O to here... H2S + 2OH– → S2– + 2H2O


AB + CD = AD + CB H2=A;S=B;K=C;(OH)=D [AD]=H2+(OH)=H2O [CB]=K+S=KS