Question

11u=5v+35. 8v=6u+62 how do I eliminate these?

Answer 1

`\left \{ {{11u=5v+35} \atop {8v=6u+62}} \right. \\\\ \left \{ {11u-5v=35\ \ \ \atop \cdot5} \right. \\\\ \left \{ {{88u-40v=280} \atop {-30u+40v=310}} \right. \\+------\\\\58u=590\ \ \ |:58\\u=(590)/(58)=(295)/(29)=10(5)/(29)\\\\8v=6\cdot(295)/(29)+35\\8v=(1770)/(29)+(1015)/(29)\\8v=(2785)/(29)\ \ \ \ |\cdot(1)/(8)\\v=(2785)/(232)=12(1)/(232)`