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A baseball player slides into third base with an initial speed of 8.55 m/s. If the coefficient of kinetic friction between the player and the ground is 0.45, how far does the pl…
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A baseball player slides into third base with an initial speed of 8.55 m/s. If the coefficient of kinetic friction between the player and the ground is 0.45, how far does the pl…
asked
Jul 25, 2017
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A baseball player slides into third base with an initial speed of 8.55 m/s. If the coefficient of kinetic friction between the player and the ground is 0.45, how far does the player slide before coming to rest?
Mathematics
high-school
Laurine
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Laurine
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1
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Vi=8.55m/s
Ff
=
Uk
mg=0.45m(9.8m/
s2
)
Calculate the acceleration (which will be negative since it's due to the force of friction):
a=
Fm
a=
(0.45)(9.8m/
s2
)m
m
a=4.41m/
s2
Time to stop:
t=
8.55m/s
4.41m/
s2
=1.94s
Now see how far they go in 1.94s with an acceleration of -4.41m/s^2:
x=
V0
t+
12
a
t2
x=(8.55m/s)(1.94s)+
12
(−4.41m/
s2
)(1.94s
)2
=8.29m
Ragerory
answered
Jul 30, 2017
by
Ragerory
7.9k
points
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