Question

When equal volumes of 0.5 M H2SO4 and 0.5 M NaOH are mixed, the resulting solution is

Answer 1

The concentration of mixed solution = 0.5 M

Further explanation

Given

0.5 M H₂SO₄

0.5 M NaOH

Required

The concentration

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂

m = mixed solution

V = volume

M = molarity

V = mixed volume

1 = solution 1

2 = solution 2

Vm = V₁+V₂

Equal volumes⇒V₁=V₂, and Vm = 2V, then equation becomes :

2V.Mm = V(M₁+M₂)

2V.Mm = V(0.5+0.5)

Mm=0.5 M