Question

what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Answer 1

7 and 1/8. all you need to do is add these together by getting a common denominator of eight

Answer 2

`8(1)/(8)`

Explanation:

The sides of the triangle are
`2 (1)/(8) \:\text{feet}` ,
`3 (1)/(2) \:\text{feet}`, and
`2 (1)/(2) \:\text{feet}`

We need to find the distance around a triangle, so we have to add all the three sides.

So, the distance around a triangle is
`2 (1)/(8)+3 (1)/(2)+2 (1)/(2)`

`=2+3+2+(1)/(8) +(1)/(2) +(1)/(2)`

`=7+1+(1)/(8)`

`=8+(1)/(8)`

`=8(1)/(8)` feet

Hence, the distance around a triangle that has sides measuring
`2 (1)/(8) \:\text{feet}` ,
`3 (1)/(2) \:\text{feet}`, and
`2 (1)/(2) \:\text{feet}` is
`8(1)/(8)` feet.