Mass of Na₂SO₄= 14.346 g
Further explanation
Given
17 g NaHCO₃
0.4 mol H₂SO₄
Required
mass of Na₂SO₄
Solution
Reaction
H₂SO₄ (aq) + 2 NaHCO₃ (aq) ⇒ Na₂SO₄(aq) + 2 CO₂(g) + 2 H₂O (l)
mol NaHCO₃ :
= mass : MW
= 17 g : 84 g/mol
= 0.202
Find limiting reactant = mol : coefficient
H₂SO₄ = 0.4 : 1 = 0.4
NaHCO₃ = 0.202 : 2 = 0.101
NaHCO₃ as a limiting reactant (smaller ratio)
Mol Na₂SO₄ based on mol NaHCO₃
From the equation, mol ratio NaHCO₃ : Na₂SO₄ = 2 : 1, so mol Na₂SO₄ :
= 1/2 x mol NaHCO₃
= 1/2 x 0.202
= 0.101
Mass of Na₂SO₄ :
= mol x MW
= 0.101 x 142,04 g/mol
= 14.346 g