Question

a spinner is divided into eight equal parts numbered 1 to 8. if the spinner is spun once, what is the probability that it stops on a number that is a multiple of 2?

Answer 1

`(1)/(2)`, which is 50% probability.

Explanation:

The spinner equally divided into 8 parts and named as 1, 2, 3, 4, 5, 6, 7 and 8.

It is spun once, we need to find the probability of getting a number that is a multiple of 2.

Let's find the multiples of 2: 2, 4, 6, and 8

The total number favorable outcomes = 4

The number of possible outcomes = 8

The probability of an event = The number of favorable outcomes / The total number of possible outcomes.

Therefore, the probability that it stops on a number that is a multiple of 2 =
`(4)/(8)`

When we simplify this fraction, we get

=
`(1)/(2)`

Which is 50% probability.