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L{sin^3 (at)} so for I have this: L{ sin(at) * [1/2 ( 1 - cos(2at)]} 1/2 L{sin(at)} - 1/2 L{cos(2at)*sin(at)} 1/2 * (a^2)/(s^2 + a^2) - 1/2 L{cos(2at)*sin(at)} How do i get rid of the cos(2at)*sin(at)
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L{sin^3 (at)}

so for I have this:
L{ sin(at) * [1/2 ( 1 - cos(2at)]}
1/2 L{sin(at)} - 1/2 L{cos(2at)*sin(at)}
1/2 * (a^2)/(s^2 + a^2) - 1/2 L{cos(2at)*sin(at)}

How do i get rid of the cos(2at)*sin(at) ?

User VanThaoNguyen
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6 votes
see the attachment for detailed solution
L{sin^3 (at)} so for I have this: L{ sin(at) * [1/2 ( 1 - cos(2at)]} 1/2 L{sin(at-example-1
L{sin^3 (at)} so for I have this: L{ sin(at) * [1/2 ( 1 - cos(2at)]} 1/2 L{sin(at-example-2
User Dimi
by
8.1k points
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