Question

The following table is a valid probability distribution for a random variable X. What must be the value forP(2) to complete the table?X0123a. 0.15b. 0.2P(X)0.150.20.4C. 0.25d.0.3

Answer 1

Given:

There are given the table of probability distribution to find the value of p(2).

Step-by-step explanation:

To find the value of the probability distribution of p(2), we need to use their formula:

So,

From the formula:

`P(2)=1-(x_(0)p(x_(0))+x_(1)p(x_(1))+x_(3)p(x_(3)))`

So,

Put all the values one by one from the table into the given formula:

So,

`\begin{gathered} P(2)=1-(x_0p(x_0)+x_1p(x_1)+x_3p(x_3)) \\ =1-(0.15+0.2+0.4) \\ =1-(0.75) \\ =0.25 \end{gathered}`

Final answer:

Hence, the value of p(2) is 0.25.