Question

If the solubility of a gas is 7.5 g/L at 404 kPa pressure, what is the solubility of the gas when the pressure is 202 kPa? Show your work.

Answer 1

Data:

C1 (initial concentration) = 7.5 g/L
P1 (initial pressure) = 404 kPa
C2 (final concentration) = ? (g/L)
P2 (final pressure) = 202 kPa

We apply the data to the formula of the solubility of gases in a liquid (Henry's Law), let us see:


`\boxed{ (C_1)/(P_1) = (C_2)/(P_2)}`

Solving:


`(7.5)/(404) = (C_2)/(202)`


`404*C_2 = 7.5*202`


`404C_2 = 1515`


`C_2 = (1515)/(404)`


`\boxed{\boxed{C_2 = 3,75\:g/L}}\end{array}}\qquad\checkmark`

I hope this helps. =)