o solve this, first convert the sample into moles.
35.12g Au * (1mol/197g) = 0.18 mol Au
Then, using this mole value, convert into atoms by multiplying by Avogadro's number:
0.18 mol * (6.022 * 10^23 atoms/1 mol) = 1.08*10^23 atom
2. Again, start by converting to moles using the molar mass:
12 mol C = 12*12 = 144g
22 mol H = 22*1 = 22g
11 mol O = 11*16 = 176 g
---------------------------------------...
C12H22011 = 144+22+176 = 342g/mol
Then use that value to convert the mass to moles.
2
1.202g C12H22O11 * (1mol / 342g) = 3.5*10^-3 mol C12H22O11
b. 3.5*10^-3 * (144/342) = 1.5*10^-3mol C
etc.
follow the same procedure as b, but with atom value