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Bromine and nitrogen combine to form nitrogen tribromide (NBr3). How many liters of NBr3 gas are produced when 6.85 L of bromine reacts with excess nitrogen? Assume conditions are at STP.

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Answer:

4.567 ltr

Step-by-step explanation:

both are gases

so

N2 +Br2 =NBr3

balancing

N2 +3B2 = 2 NBr3

now

3 litr of B2 gives 2 liter of NBr3

6.85 litr of B2 gives 2/3 *6.85 litr NBr3 = 4.567ltr

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