Question

Graph the function below giving 4 points on the graph.

Answer 1

The given function is:

`f(x)=\sqrt[]{x+2}`

For simplicity, select the values of x such that the graph will take integral values.

`\begin{gathered} x=-2;f(x)=\sqrt[]{-2+2}=0\Rightarrow(-2,0) \\ x=2;f(x)=\sqrt[]{2+2}=2\Rightarrow(2,2) \\ x=7;f(x)=\sqrt[]{7+2}=3\Rightarrow(7,3) \\ x=14;f(x)=\sqrt[]{14+2}=4\Rightarrow(14,4) \end{gathered}`

Graph the function as shown below: