Answer:
2.84 s.
Step-by-step explanation:
From the question given above, the following data were obtained:
Length (L) of string = 2 m
Period (T) =?
The period of oscillation can be obtained as follow:
T = 2π√(L/g)
NOTE:
Pi (π) = 3.14
Acceleration due to gravity (g) = 9.8 m/s².
T = 2 × 3.14 × √(2/9.8)
T = 6.28 × √(2/9.8)
T = 2.84 s
Therefore, the period of oscillation is 2.84 s