92.0k views
4 votes
What is the domain and range for y=sqrt(x-4)?

User Wet Feet
by
8.5k points

1 Answer

7 votes

Domain: set of all numbers that can be inputted into a function

Since you cannot take the square root of a negative number, this means that x-4 CANNOT be negative. So it's either 0 or it's positive.
So.. x−4≥0
x−4+4≥0+4
x≥4

So this says: "Any number greater than or equal to 4 will result in x-4 being either 0 or some positive number"
So this means that the domain is

x≥4

This basically says: "the domain is the set of all numbers x such that x is greater than or equal to 4"

In interval notation, the domain is [4,∞)


The range is the set of all possible outputs. We can find the most extreme point of the range by plugging in the most extreme value for the domain
sqrt(x-4) =
sqrt(4-4) = sqrt(0) = 0

So the smallest possible output is y=0, which means that the range is
y

This basically says: "the range is the set of all numbers y such that y is greater than or equal to 0"

In interval notation, the range is

[0,∞)

User Bentedder
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories