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Look at the triangle.

What is the value of sin x°?
(A) 5 ÷ 13
(B) 12 ÷ 5
(C) 12 ÷ 13
(D) 5 ÷ 12

Look at the triangle. What is the value of sin x°? (A) 5 ÷ 13 (B) 12 ÷ 5 (C) 12 ÷ 13 (D-example-1

2 Answers

0 votes
5/13 because it the right answer

User Tyrrrz
by
8.3k points
4 votes

Answer:

option (c) is correct.


\sin x=(12)/(13)

Explanation:

Given a triangle with base 12 cm , perpendicular = 5 cm and hypotenuse = 13 cm

We have to find the value of sin x° and choose the correct option.

Lets first name the given triangle as ΔABC, as shown in figure below.

We know the value of trigonometric ratio sine is ,


\sin\theta=(Perpendicular)/(Hypotenuse)

Here,
\theta=x

and for x to be angle, perpendicular is AB and hypotenuse is AC.


\sin x=(AB)/(AC)

Substitute the values, we get,


\sin x=(12)/(13)

Thus, option (c) is correct.

Look at the triangle. What is the value of sin x°? (A) 5 ÷ 13 (B) 12 ÷ 5 (C) 12 ÷ 13 (D-example-1
User Hua
by
8.2k points