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Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object.

Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N-example-1
User Badrul
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1 Answer

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The magnitude and direction (relative to the x axis) of the acceleration of the object is 20.03 m/s² along x - axis.

How to calculate the magnitude of the acceleration?

The magnitude and direction (relative to the x axis) of the acceleration of the object is calculated as follows;

Fx = ma

The magnitude of the force along x - direction is calculated as;

Fx = F cos(θ)

Fx = 51 N x cos (45) + 40 N x cos (0)

Fx = 36.1 N + 40 N

Fx = 76.1 N

The magnitude of the acceleration is calculated as follows;

a = Fx / m

a = ( 76.1 N ) / ( 3.8 kg)

a = 20.03 m/s²

User Pamala
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