Question

Sid is packing crushed ice into a cone-shaped cThe cone has a height of 5 in. Its base has a diameter of 4 in. What is thevolume of the cone?20 320 in80 380r in 3

Answer 1

`The\ volume\ of\ the\ cone:V=(1)/(3)\pi r^2H\\\\H=5\ in\\2r=4\ in\to r=2\ in\\\\subtitute\\\\V=(1)/(3)\pi\cdot2^2\cdot5=(1)/(3)\pi\cdot4\cdot5=(20)/(3)\pi\ (in^3)\\\\Answer:\boxed{V=(20)/(3)\pi\ in^3}`

Answer 2

(A) The volume of the cone is
`(20)/(3){\pi}inches^3`.

Explanation:

It is given that the cone has a height of 5 inches and the base has the diameter equals to 4 inches, therefore the radius of the cone can be obtained as:

`Radius=(Diameter)/(2)`

`Radius=(4)/(2)=2`inches

And height=5inches

Now, the volume of the cone is obtained as:

`v=(1)/(3){\pi}r^2h`

Substituting the given values, we get

`v=(1)/(3){\pi}(2)^2(5)`

`v=(20)/(3){\pi}inches^3`

Thus, the volume of the cone is
`(20)/(3){\pi}inches^3`.

Hence, option A is correct.