Question

The diagram shows 2 wheels of radii 15 cm and 24 cm. Their centres, H and K, are 41 cm apart. ( Refer to the attatchment given )

Help me find the lengthof the belt by providing workings. Thanks!

Answer 1

Hello,


`1) \\ cos(\widehat{HKR})= (9)/(41) ==\ \textgreater \ \widehat{HKR}=1.34948188...rad\\\\ sin(\widehat{KHR})= (9)/(41) ==\ \textgreater \ \widehat{KHR}=0,22131444...rad\\\\`


`\widehat{QKA}=\pi-1,34948188...=1,792110769...rad\\\\ $\overset{\frown}{QA}$=24*1,792110769...=43,010658459...\\\\ \widehat{KHB}= (\pi)/(2)-0,22131444...=1,3494888...\\\\ $\overset{\frown}{PB}$=15*1,3494888...=20,2422282\\\\`

2)

`|HR|=√(9^2+41^2) =41,976183723\\\\`


length=2*(43,010658459+20,2422282+41,976183723)=210,458140764