Question

suppose a 14-gram sample of iron is heated from 20.0°c to 25.0°c. the specific heat of iron is 0.11 cal/g°c. how much heat energy was absorbed by the iron?

Answer 1

Q=7.7

Step-by-step explanation:

Answer 2

Q = ?

Cp = 0.11 cal/gºC

Δt = 25.0 - 20.0 => 5 ºC

m = 14 g

Q = m x Cp x Δt

Q = 14 x 0.11 x 5

Q = 7.7 cal

hope this helps!