Question

F(x) = x3 + 4x2 + x − 6 real zeros

Answer 1

Hello,

f(x)=x^3+4x²+x-6
=x^3-x²+5x²-5+x-1
=x²(x-1)+5(x-1)(x+1)+x-1
=(x-1)(x²+5x+5+1)
=(x-1)(x²+2x+3x+6)
=(x-1)(x(x+2)+3(x+2))
=(x-1)(x+2)(x+3)

Zeros are 1,-2,-3.