Question

If 32.5 grams of calcium oxide is reacted, how much calcium fluoride will be produced in the reaction?The answers could be A) 9.58 gramsB) 23.3 gramsC) 12.2 grams D) 45.2 grams

Answer 1

First, let's convert 32.5 grams of calcium oxide (CaO) in moles, using its molar mass which is 56.08 g/mol:

`32.5\text{ g CaO}\cdot\frac{1\text{ mol CaO}}{56.08\text{ g CaO}}=0.579\text{ moles CaO.}`

In the chemical equation, you can see that 1 mole of CaO reacting, produces 1 mol of CaF2. The mole ratio between these two compounds is 1:1, so 0.579 moles of CaO is producing 0.579 moles of CaF2.

The final step is to convert 0.579 moles of CaF2 to grams using its molar mass which is 78.08 g/mol:

`0.579molesCaF_2\cdot(78.08gCaF_2)/(1molCaF_2)=45.2gCaF_2.`

The answer is that 32.5 grams of calcium oxide (CaO) reacted, producing 45.2 grams of calcium fluoride (CaF2).